x^2+8x+16/3x+12

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Solution for x^2+8x+16/3x+12 equation: 


x in (-oo:+oo)

x^2+8*x+(16/3)*x+12 = 0

x^2+40/3*x+12 = 0

DELTA = (40/3)^2-(1*4*12)

DELTA = 1168/9

DELTA > 0

x = ((1168/9)^(1/2)-40/3)/(1*2) or x = (-(1168/9)^(1/2)-40/3)/(1*2)

x = ((1168/9)^(1/2)-40/3)/2 or x = (-((1168/9)^(1/2)+40/3))/2

x in { (-((1168/9)^(1/2)+40/3))/2, ((1168/9)^(1/2)-40/3)/2 }

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